Logical Deduction Flashcards
6 cards from real Abstract Reasoning practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 6 Logical Deduction flashcards as text
All squares in a test are shaded. Figure X is not shaded. Which conclusion is valid?
Answer: Figure X is not a square
If all squares are shaded and Figure X is not shaded, then by contrapositive, Figure X cannot be a square.
In a logical abstract test: Shape A is bigger than Shape B. Shape B is bigger than Shape C. Which conclusion must be true?
Answer: Shape A is bigger than Shape C
Transitivity of inequality: A > B and B > C implies A > C.
Every circle in the set is blue, and every blue shape is large. Shape Z is a circle. What must be true about Shape Z?
Answer: Shape Z is blue and large
Circle → blue (premise 1), and blue → large (premise 2); by transitivity, circle → blue and large.
In an abstract test, if a figure has more than 4 sides, it is placed in Group A. A hexagon has 6 sides. Which group does it belong to?
Answer: Group A
6 > 4, so the hexagon satisfies the condition and belongs to Group A.
No triangles are shaded. Shape P is shaded. What can you conclude about Shape P?
Answer: Shape P is not a triangle
Since no triangles are shaded and Shape P is shaded, Shape P cannot be a triangle.
In a deductive abstract problem: if a shape is red, it is also round. If a shape is round, it has no corners. Shape Q is red. What must be true about Shape Q?
Answer: Shape Q has no corners
Red → round (rule 1), and round → no corners (rule 2); chaining gives red → no corners, so Shape Q has no corners.