FREE OAR Math Skills Question and Answers
What is the value of x if 16x + 4 = 100?
Explanation:
First, subtract 4 from both sides to isolate the variable, Then, divide both sides by 16 to solve for x:
16x + 4 - 4 = 100 - 4
16x = 96
16x/16 = 96/16
x = 6
What is the ratio of Tinalco Limited's first-year coal production to Alcom Plc's anticipated second-year coal production?
Explanation:
Tinalco Year 1: Alcom plc's Year 2
900,000: 450,000
900,000 / 450,000 = 2 = 1:0.5
How many of the cogs made in March and May were unsatisfactory?
Explanation:
March substandard = 1,000
May substandard = 3,000
Total = 4,000
Total March = 7,000
Total May = 10,000
Overall Total = 17,000
4,000 / 17, 000 × 100 = 23.5%
How many of the gears created in March and April weren't of a high standard?
Explanation:
March total = 7,000 cogs
March substandard = 1,000 cogs
7,000 - 1,000 = 6,000 cogs
April total = 8,000 cogs
April Substandard = 3,000 cogs
8,000 - 3,000 = 5000 cogs
6,000 + 5,000 = 11,000
Only 20% of the retail price of a typical cog may be charged for a subpar cog. If a regular cog was subsequently sold for $1.99 and it was assumed that every cog made in May was sold, how much revenue was earned from all cog sales in May?
Explanation:
Step 1 - Calculate the value of standard cogs sold:
Number of standard cogs = total - substandard: 10,000 - 3,000 = 7,000 Standard cogs
Each cog worth $1.99, so total = 7,000 x $1.99 = $13,930
Step 2 - Calculate the value of substandard cogs sold
Number of substandard cogs = 3,000
Value of each = 20% of standard value: 0.2 x $1.99 = $0.398 = $0.40 to nearest cent
Total: $0.4 x 3,000 = $1,200
Step 3 - Total
13,930 + 1,200 = $15,130
What was the entire increase in cog manufacturing from February to April in percentage terms?
Explanation:
April cog production = 8,000
Feb cog production = 4,000
8,000-4,000 / 4,000 ×100 = 100%
A $20,000 car loses value every year until only the metal and components are left. Which of the following equations can accurately be used to calculate the car's value at T years after purchase if it takes the car 15 years to lose all value other than the metal and parts, and the metal and parts are worth $755?
Explanation:
If a $20,000 car will only be worth $755 at the very least, that means the car will lose $19,245 in value over the course of 15 years ($20,000 – $755 = $19,245).
Every year, $1,283 is lost ($19245 x 15).
As a result, the formula is 1,283T + 20,000.