FREE Building React App Questions and Answers

ReactJS does not need HTML or any of the HTML preprocessor to make UI elements

False

True

Correct! Wrong!

About lists in React, why should we use "keys"?

The keys are mandatory to prevent the application from stopping.

The braces interrupt the information listing flow.

Keys are not mandatory.

Keys help React identify which items have changed.

Correct! Wrong!

About hooks it is incorrect to say:

Hooks don't work inside classes and allow you to use React without classes.

Hooks are functions that allow you to hook into React's state and lifecycle features from within functional components.

Hooks work inside classes and allow you to use React without classes.

We can create our own hooks.

Correct! Wrong!

Is the use of JSX mandatory to develop with React?

Yes

Sometimes

Correct! Wrong!

What is the result of the expression

const [add, setSum] = useState(0)
setSum(add + 4)
setSum(adding - (1x2))

Correct! Wrong!

Props can be modified in child component directly like state

False

True

Correct! Wrong!

We can integrate reactJS in any of the existing web app

False

True

Correct! Wrong!

FREE Building React App Questions and Answers

ReactJS does not need HTML or any of the HTML preprocessor to make UI elements

About lists in React, why should we use "keys"?

About hooks it is incorrect to say:

Is the use of JSX mandatory to develop with React?

What is the result of the expression

const [add, setSum] = useState(0)
setSum(add + 4)
setSum(adding - (1x2))

Props can be modified in child component directly like state

We can integrate reactJS in any of the existing web app

FREE Introducing React Hooks Questions and Answers

FREE React Javascript Questions and Answers

ReactJS does not need HTML or any of the HTML preprocessor to make UI elements

About lists in React, why should we use "keys"?

About hooks it is incorrect to say:

Is the use of JSX mandatory to develop with React?

What is the result of the expression const [add, setSum] = useState(0) setSum(add + 4) setSum(adding - (1x2))

Props can be modified in child component directly like state

We can integrate reactJS in any of the existing web app

Premium Tests $49/moFREE April-2024

What is the result of the expression

const [add, setSum] = useState(0)
setSum(add + 4)
setSum(adding - (1x2))

Premium Tests $49/mo
FREE April-2024