FREE BMAT Assessment Trivia Questions and Answers
A "gold medal," which is used on occasions like the Olympic Games, is composed of a silver-nickel alloy with a gold-silver alloy covering.
The medal weighs 256 g, of which the coating's mass is 24.0 g.
The gold-silver alloy has a density of 16.0 g cm-3 while the silver-nickel alloy has a density of 10.0 g cm-3.
What is the medal's volume?
Explanation:
Mass = density x volume, so volume = mass/density.
Mass of the gold-silver coating = 24g.
Mass of the silver-nickel = 256-24=232g.
Volume of the gold-silver coating = 24/16=1.5cm3
Volume if the silver-nickel = 232/10=23.2cm3.
Therefore the total volume of the medal must be 1.5+23.2=24.7cm3.
A submarine employs sound with a frequency of 6000Hz to identify obstacles in the water in front of it.
This sound's pulse is reflected by a target 750 meters in front of the submarine. One second after being delivered, the pulse is received by the submersible.
What is this sound's wavelength in the ocean?
Explanation:
The sound travels to the object in front of the submarine and then back again, so travels 750×2=1500m.
Speed= distance/time
=1500/1
=1500 m/s
Velocity= frequency x wavelength,
so wavelength= velocity/frequency
=1500/6000
=0.25m=25cm.
A deep freezer with an open top is a common feature in supermarkets to keep food frozen but accessible to customers.
Which of the following descriptions of the air in this open-topped freezer best explains why the products stay frozen?
Explanation:
When compared to warmer air, the particles in colder air have less energy, move less frequently, and are arranged more orderly and closely together. As a result, cold air has a higher density than warm air. In order to keep the items close to the bottom of the freezer frozen despite the warmer air above, there would be a graduation of colder to warmer air traveling from the bottom to the top of the freezer.
Human stem cells are being used by researchers to create remedies for a wide range of health issues.
For this task, two kinds of stem cells are available:
• stem cells taken from a developing embryo
• Adult bone marrow stem cells were used.
1. Both of these stem cell varieties are capable of procreating daughter cells. The donor's genome will be present in one haploid copy in each daughter cell.
2. Embryonic stem cells can develop into a wider range of specialized cells than adult bone marrow stem cells can.
3. Using stem cell therapy to address a medical ailment can make a person more likely to get cancer.
Which of the aforementioned claims is true? (Assume no mutations take place.)
Explanation:
Because all stem cells divide by mitosis to create genetically identical diploid daughter cells, Statement 1 is untrue.
Statement 2 is accurate because adult bone marrow cells are multipotent, whereas stem cells derived from early embryos are totipotent (can develop into any cell type) (can differentiate into a few defined cell types).
Statement 3 is also true because if stem cells continue to divide, a tumor may develop.
Only statements 2 and 3 are thus accurate.
The regular cost of a camera is 20% less during a sale.
The camera is available for purchase for £180.
Which expression provides the camera's standard price?
Explanation:
Normal price x 0.80 = £180
Normal price = £180/0.80.
1- Gamete production is the only possible source of genetic variation in sexual reproduction.
2- The environment can cause genetic variation.
3- Mutations can produce genetic variation.
4- Asexual reproduction always produces genetic variation.
Which of the following two assertions regarding genetic variation is true?
Explanation:
Statement 1 is likewise untrue because genetic variation can result from mutations as well.
Statement 2 is true because the environment can change gene expression (epigenetic variation), which can affect genetic variation.
Statement 4 is false because asexual reproduction results in children that are genetically identical to their parents and so to one another.
According to the justification for statement 1, statement 3 must thus be accurate.
Only statements 2 and 3 are thus accurate.
There is a hereditary issue in some rabbits. This condition is encoded by the dominant allele.
The condition was passed from a homozygous dominant rabbit to a rabbit without it by mating.
They produced three children.
After mating with a rabbit that wasn't affected, one of the offspring again produced three offspring. One child did not have the ailment, whereas the other two did.
Each of the three generations of rabbits has one body cell that is in the early stages of interphase.
How many copies of the conditional allele do these cells collectively contain overall?
Explanation:
Let R be the dominant allele and r be the recessive allele for this condition.
RR x rr can be used to symbolize the cross between the homozygous dominant rabbit and a rabbit without the condition.
This cross can only result in the genotype Rr, which is the only feasible outcome.
Then, Rr x rr, a rabbit having genotype Rr was mated with a rabbit lacking the condition.
The gene Rr must have been present in two of the kids from this cross because they both had the disease.
One of the offspring must have had the genotype rr because they did not all get the disease.
Consequently, each generation of rabbits has the following genotypes:
1st gen = RR, rr
2nd gen = Rr, Rr, Rr
3rd generation is RRRRRR.
Therefore, there would be seven copies of the R allele overall.
