Free Amazon MBA: Clock and Calendar Questions and Answers 1 — Questions and Answers
Question 1: How many times a day are a clock's hands straight?
- 36
- 44 (Correct answer)
- 22
- 48
Correct answer: 44
A clock's hands are straight when they are either coincident (0 degrees apart) or exactly opposite (180 degrees apart). In a 12-hour period, the hands coincide 11 times and are opposite 11 times. Therefore, in a full 24-hour day, this occurs 22 times for coincidence and 22 times for opposition, totaling 44 times.
Question 2: Thursday is today. the 91st day. As follows:
- Monday
- Sunday
- Thursday (Correct answer)
- Tuesday
Correct answer: Thursday
To determine the day of the week 91 days from Thursday, we need to find the remainder when 91 is divided by 7, as there are 7 days in a week. Since 91 divided by 7 is exactly 13 with a remainder of 0, the 91st day will fall on the same day of the week as today. Therefore, the 91st day will also be a Thursday.
Question 3: At 7 am, a clock is set to display the right time. Monday. The time is off by 15 minutes in 24. When the clock reads 6 am on the next Friday, what hour will it actually be?
- 6:15 am Friday
- 7:15 am Friday
- 7 am Friday (Correct answer)
- 6:30 am Friday
Correct answer: 7 am Friday
The clock loses 15 minutes every 24 actual hours, meaning it shows 23 hours and 45 minutes (23.75 hours) for every 24 actual hours. From Monday 7 am to Friday 6 am on the faulty clock, 95 hours have passed. Using the ratio (Actual Time / Faulty Time) = (24 / 23.75), we find that 95 faulty hours correspond to 96 actual hours. Adding 96 actual hours to Monday 7 am brings us to Friday 7 am.
Question 4: At six in the morning, a clock is set to start. When it reads 11 o'clock in the morning, by how many degrees will the hour rotate the clock?
- 160°
- 150° (Correct answer)
- 140°
- 180°
Correct answer: 150°
The hour hand of a clock completes a full 360-degree rotation in 12 hours. This means it moves 30 degrees every hour (360 degrees / 12 hours). From 6 am to 11 am, a total of 5 hours have passed. Therefore, the hour hand will have rotated 5 hours * 30 degrees/hour = 150 degrees.
Question 5: How many degrees will the hour hand rotate when an accurate clock reads 2 o'clock in the afternoon at 8 o'clock in the morning?
- 140°
- 180° (Correct answer)
- 168°
- 150°
Correct answer: 180°
The hour hand moves 30 degrees for every hour that passes (360 degrees / 12 hours). From 8 o'clock in the morning to 2 o'clock in the afternoon, a total of 6 hours have elapsed. Therefore, the hour hand will have rotated 6 hours * 30 degrees/hour = 180 degrees.
Question 6: Of the following, which is not a leap year?
- 800
- 700 (Correct answer)
- 1200
- 2000
Correct answer: 700
A year is a leap year if it is divisible by 4, unless it is a century year (divisible by 100). Century years are only leap years if they are also divisible by 400. 700 is divisible by 4 and by 100, but it is not divisible by 400, making it the only non-leap year among the options.
Question 7: Saturday, December 8, falls. On December 8, 2006, what day of the week was it?
- Monday
- Tuesday
- Saturday
- Friday (Correct answer)
Correct answer: Friday
To find the day of the week for December 8, 2006, we can calculate the number of odd days from a known reference point. January 1, 2006, was a Sunday. Counting the days from January 1, 2006, to December 8, 2006, gives a total of 341 days. Dividing 341 by 7 (days in a week) gives a remainder of 5. Adding 5 days to Sunday (the starting day) results in Friday.
Question 8: 2007-01-01 was a Monday. Which day of the week is January 1, 2008?
- Sunday
- Wednesday
- Friday
- Tuesday (Correct answer)
Correct answer: Tuesday
A normal year has 365 days. To find the day of the week for the same date in the following year, we calculate the number of 'odd days' by dividing 365 by 7. 365 divided by 7 leaves a remainder of 1. Therefore, January 1, 2008, will be one day after January 1, 2007. Since January 1, 2007, was a Monday, January 1, 2008, will be a Tuesday.
Question 9: Which day of the week, if any, was it on December 8, 2006?
- Tuesday
- Saturday
- Friday (Correct answer)
- Sunday
Correct answer: Friday
To determine the day of the week for December 8, 2006, we can use a calendar algorithm or count odd days from a known reference. Using January 1, 2006, as a Sunday, and counting the 341 days until December 8, 2006, we find 341 divided by 7 leaves a remainder of 5. Adding 5 days to Sunday (0) gives us Friday.
Question 10: What day of the week was it on March 6, 2004, which is Monday in 2005?
- Saturday
- Wednesday
- Friday
- Sunday (Correct answer)
Correct answer: Sunday
We are given that March 6, 2005, was a Monday and need to find the day for March 6, 2004. The year 2004 was a leap year, and the period from March 6, 2004, to March 6, 2005, includes February 29, 2004. Therefore, there are 366 days in this interval. Since 366 days is equivalent to 52 weeks and 2 odd days, we subtract 2 days from Monday to find the day for March 6, 2004, which results in Sunday.
Question 11: How many times will the hour needle and minute needle be together between now and twelve hours?
- 19 times
- 13 times
- 11 times (Correct answer)
- 15 times
Correct answer: 11 times
In a 12-hour period, the minute hand overtakes the hour hand 11 times. They coincide once every hour, except for the period between 11 o'clock and 1 o'clock, during which they only coincide exactly at 12 o'clock. Therefore, in any 12-hour duration, the hour and minute hands will be together exactly 11 times.
Question 12: Every Sunday and the second Saturday are holidays. How many working days are there in a month that starts on a Saturday and lasts 30 days?
- 24 (Correct answer)
- 23
- 22
- 21
Correct answer: 24
In a 30-day month starting on a Saturday, there will be 5 Sundays (days 2, 9, 16, 23, 30) and 5 Saturdays (days 1, 8, 15, 22, 29). The holidays are all 5 Sundays and the second Saturday (day 8). This totals 5 + 1 = 6 holidays. Therefore, the number of working days is 30 (total days) - 6 (holidays) = 24 working days.
Question 13: It's Monday today. It will be 61 days later when...
- Saturday (Correct answer)
- Monday
- Thursday
- Sunday
Correct answer: Saturday
To find the day of the week 61 days from Monday, we need to determine the remainder when 61 is divided by 7 (the number of days in a week). 61 divided by 7 is 8 with a remainder of 5. Therefore, we add 5 days to Monday, which results in Saturday.
Question 14: In the same amount of time that the second hand moves 4800 degrees, how many degrees will the minute hand move?
- 60
- 90
- 70
- 80 (Correct answer)
Correct answer: 80
The second hand moves 360 degrees in 60 seconds (1 minute), so it moves at 6 degrees per second. The minute hand moves 360 degrees in 60 minutes, which is 6 degrees per minute. If the second hand moves 4800 degrees, it takes 4800 / 360 = 40/3 minutes. In this same duration, the minute hand will move (40/3 minutes) * (6 degrees/minute) = 80 degrees.
Question 15: What day will it be on the nineteenth day of the month if the seventh day of the month is three days earlier than Friday?
- Sunday (Correct answer)
- Wednesday
- Monday
- Saturday
Correct answer: Sunday
First, determine the day of the week for the seventh day of the month. If it is three days earlier than Friday, then it is Tuesday (Friday - 3 days = Tuesday). Next, calculate the difference in days between the 19th day and the 7th day, which is 12 days. To find the day of the week, find the remainder of 12 divided by 7, which is 5. Adding 5 days to Tuesday results in Sunday.
Question 16: What day of the week was August 16, 1947?
- Friday
- Thursday
- Wednesday
- Saturday (Correct answer)
Correct answer: Saturday
To determine the day of the week for August 16, 1947, a standard calendar algorithm is used. This involves summing the day (16), month code (August is 2 for non-leap years), the last two digits of the year (47), the number of leap years within those 47 years (11), and the century code for the 1900s (0). The total sum (16+2+47+11+0 = 76) is then divided by 7. A remainder of 6 corresponds to Saturday.
How many times a day are a clock's hands straight?