FREE Banking Exam Quantitative Aptitude Question and Answers
73, 77, 85, 99, ?
To find the pattern in the given sequence (73, 77, 85, 99), let's examine the differences between consecutive terms: 77 - 73 = 4 85 - 77 = 8 99 - 85 = 14 The differences between consecutive terms are increasing by multiples of 4. To find the next difference: 14 + 4 = 18 Now, let's add this difference to the last term in the sequence: 99 + 18 = 117
The ratio of 15 to A to B is 10. B is 22 less than 3 times A if 10 is deducted from it. How much do A and B add up to?
15 times A is equal to 10 times B: 15A = 10B If 10 is subtracted from B, it is 22 less than 3 times A: B - 10 = 3A - 22 Now, let's solve these equations to find the values of A and B. From the first equation, we can express A in terms of B: A = (10/15)B A = (2/3)B Now, substitute this value of A into the second equation: B - 10 = 3((2/3)B) - 22 B - 10 = 2B - 22 B - 2B = -22 + 10 -B = -12 B = 12 Now, we can find the value of A using the first equation: A = (2/3) * 12 A = 8 The sum of A and B is: Sum = A + B Sum = 8 + 12 Sum = 20 Therefore, the sum of A and B is 20.
17, 21, 37, 73, ?
The pattern in the given sequence is as follows: 17 (Prime) × 2 + 7 = 37 (Prime) 21 (Prime) × 2 - 5 = 37 (Prime) 37 (Prime) × 2 - 3 = 73 (Prime) 73 (Prime) × 2 + 1 = 147 (Not Prime) So, the next number in the sequence is 137 (Prime).
474, 486, 510, 546,?
Let's find the pattern in the given sequence: 474 + 12 = 486 486 + 24 = 510 510 + 36 = 546 546 + 48 = 594 So, the next number in the sequence should be 594
Ali received a final grade of 35 in English, 39 in Science, 40 in Math, 37 in Hindi, and 32 in Social Studies. A student may earn a maximum of 60 points for each course. How much of a passing grade did Ali receive on this test?
To calculate Ali's overall passing grade, we need to find the average percentage of the grades he received in all subjects. Step 1: Find the total marks earned by Ali. Total marks earned = Marks in English + Marks in Science + Marks in Math + Marks in Hindi + Marks in Social Studies Total marks earned = 35 + 39 + 40 + 37 + 32 = 183 Step 2: Find the maximum marks possible. Maximum marks possible = Maximum marks per subject * Number of subjects Maximum marks possible = 60 * 5 = 300 Step 3: Calculate the percentage. Percentage = (Total marks earned / Maximum marks possible) * 100 Percentage = (183 / 300) * 100 Percentage = 0.61 * 100 Percentage = 61% So, Ali received a passing grade of 61% on this test.
A man bought two different types of alcoholic beverages. The alcohol to water ratio in the first mixture is 4:5, whereas it is 6:7 in the second. If he combines the two provided mixtures to create a third combination of 22 litres with a 5:6 alcohol to water ratio, the amount of the first mixture needed to create the third kind of mixture is.
Step 1: Write down the ratios for each mixture: Mixture 1 (4:5) contains x liters of alcohol and (x + 22) liters of water. Mixture 2 (6:7) contains (22 - x) liters of alcohol and [(22 - x) + 22] liters of water. Step 2: Write down the ratio for the desired mixture (5:6): Desired Mixture (5:6) contains 5 liters of alcohol and 6 liters of water. Step 3: Set up the equation based on the alcohol content: Total alcohol in Mixture 1 + Total alcohol in Mixture 2 = Total alcohol in Desired Mixture [(4/9) * x] + [(6/13) * (22 - x)] = 5 Step 4: Solve for x: [(4/9) * x] + [(6/13) * (22 - x)] = 5 Multiply both sides by 117 to eliminate fractions: (13 * 4 * x) + (9 * 6 * (22 - x)) = 585 52x + 594 - 54x = 585 -2x = 585 - 594 -2x = -9 x = 9 So, 9 liters of the first mixture (with the alcohol to water ratio of 4:5) are needed to create the third combination. Therefore, the correct answer is 9 liters.
9, 43, 212, 1056, ?
If we look at the differences between consecutive terms: 43 - 9 = 34 212 - 43 = 169 1056 - 212 = 844 The differences between consecutive terms do not follow a simple pattern. However, let's look at the second differences: 169 - 34 = 135 844 - 169 = 675 The second differences are not constant either. But if we look closer, we can observe that the second differences are following a pattern: they are increasing by a factor of 5. So, to find the next second difference: 675 * 5 = 3375 Now, let's add this second difference to the last term in the sequence: 1056 + 3375 = 4431 So, the next term in the sequence should be 4431. The complete sequence is: 9, 43, 212, 1056, 4431, 5275
450 kilometres are covered by a train in 6 hours. The speed of a bike is one-half that of a train. How long will it take the bike to travel 300 kilometers?
Let's first find the speed of the train. We know that the train covers 450 km in 6 hours. Speed of the train = Distance / Time = 450 km / 6 hours = 75 km/h Now, the speed of the bike is half of the speed of the train. Speed of the bike = (1/2) * Speed of the train = (1/2) * 75 km/h = 37.5 km/h Now, we can find the time taken by the bike to cover 300 km: Time = Distance / Speed = 300 km / 37.5 km/h = 8 hours So, the bike will take 8 hours to cover the distance of 300 km.
A tank can be filled by two pipelines in 20 and 24 hours, respectively. The tank can be emptied in 40 hours with a third pipe. if all three pipelines are operational and open at the same time. How long will it take the tank to fill up then?
Given: Pipe A can fill the tank in 20 hours. Pipe B can fill the tank in 24 hours. Pipe C can empty the tank in 40 hours. We've already calculated the rates: Pipe A's filling rate: 1 tank/20 hours = 1/20 tanks per hour. Pipe B's filling rate: 1 tank/24 hours = 1/24 tanks per hour. Pipe C's emptying rate: 1 tank/40 hours = -1/40 tanks per hour. When all three pipes are open and functioning simultaneously, their rates are additive: Total filling rate = (1/20) + (1/24) + (-1/40) tanks per hour = (12/240) + (10/240) - (6/240) tanks per hour = (22/240) - (6/240) tanks per hour = 16/240 tanks per hour = 1/15 tanks per hour The positive sign indicates that the tank is filling at a rate of 1/15 tanks per hour. To find how much time it takes to fill the tank, we can take the reciprocal of the total filling rate: Time to fill the tank = 1 / (1/15) hours = 15 hours
For Rs 2250, P, Q, and R rent a penthouse. If they occupied it for 8, 10, and 12 hours, respectively, R will have to pay the following rent:
Let's assume that R's rent for 12 hours is Rs. X. Now, let's calculate the proportions of rent for each person based on the hours they used: P's proportion: 8 hours / (8 hours + 10 hours + 12 hours) = 8/30 Q's proportion: 10 hours / (8 hours + 10 hours + 12 hours) = 10/30 R's proportion: 12 hours / (8 hours + 10 hours + 12 hours) = 12/30 Given that they all together paid Rs. 2250 for the penthouse, we can set up the equation: P's rent + Q's rent + R's rent = Rs. 2250 (P's proportion) * Total Rent + (Q's proportion) * Total Rent + (R's proportion) * Total Rent = Rs. 2250 (8/30) * Total Rent + (10/30) * Total Rent + (12/30) * Total Rent = Rs. 2250 Now, we can simplify the equation: (30/30) * Total Rent = Rs. 2250 Total Rent = Rs. 2250 Now, let's find the rent paid by R for 12 hours: R's rent = (R's proportion) * Total Rent = (12/30) * Rs. 2250 = Rs. 900 So, the rent paid by R for 12 hours is Rs. 900.
A dad and his son are typically 48 years old. 13 years ago, their ages were 11: 3 in proportion. What is the son's current age?
Step 1: Set up the equations based on the given information: The average age of the man and his son is 48 years: (M + S) / 2 = 48 The ratio of their ages 13 years ago was 11:3: (M - 13) / (S - 13) = 11/3 Step 2: Solve the equations simultaneously to find the values of M and S. From Equation 1, we can express M in terms of S: M + S = 96 M = 96 - S Now, substitute this value of M into Equation 2: (96 - S - 13) / (S - 13) = 11/3 Simplify the equation: (83 - S) / (S - 13) = 11/3 Cross-multiply: 3(83 - S) = 11(S - 13) Expand and solve for S: 249 - 3S = 11S - 143 Combine like terms: 14S = 392 Divide by 14: S = 392 / 14 S = 28 So, the present age of the son is 28 years.
11, 18.5, 44.5, 141, ?
The pattern in the given sequence is as follows: 11 × 1.5 + 1 = 18.5 18.5 × 2.5 - 2 = 44.5 44.5 × 3.5 - 3 = 154.75 154.75 × 4.5 - 4 = 691.375 So, the next number in the sequence should be 691.375
A salesman of fruits had some pineapples. He still has 350 pineapples after selling 30% of them. Initially, how many pineapples did he have?
Let's denote the original number of pineapples the fruit seller had as "P." According to the information given, the fruit seller sold 30% of the pineapples and still had 350 pineapples left. This can be represented by the equation: P - 0.30P = 350 Solving for P: 0.70P = 350 P = 350 / 0.70 P = 500 So, the fruit seller originally had 500 pineapples.
After two months, Mike joined Mich in his new venture. Mike spent $27,000 whereas Mich spent Rs. Their annual earnings totaled Rs. 5000. How much will Mich profit?
Given: Mike's investment = Rs. 27,000 Mich's investment = Rs. X (unknown) Total annual earnings = Rs. 5,000 Since Mike joined after two months, he was part of the venture for 10 months (2 months + 10 months = 12 months in a year). The ratio of Mike's investment to Mich's investment is: Mike's ratio = Mike's investment / Mich's investment Mike's ratio = Rs. 27,000 / X Total earnings after 12 months = Mike's profit + Mich's profit = Rs. 5,000 Now, we can set up an equation using the ratio: Mike's ratio + 1 = Total earnings / Mike's earnings Rs. 27,000 / X + 1 = Rs. 5,000 / Mike's profit Since we have the value of Mike's investment and total earnings, we can find Mike's profit: Mike's profit = Rs. 5,000 * (Rs. 27,000 / X + 1) Once we know Mike's profit, we can find Mich's profit using the total earnings: Mich's profit = Total earnings - Mike's profit Without knowing the exact value of Mich's investment (Rs. X), we cannot determine the exact profit for Mich. So, the correct answer from the provided options cannot be determined.
Sanjay made a $50,000 investment to launch a business. Ajay joined him with a contribution of Rs. 80,000 after six months. Sanjay added an additional sum of Rs. 20,000 after the business had been operating for a year. Three years later, they had a profit of Rs. 702,000. What portion of the profits goes to Sanjay ?
Given: Sanjay's initial investment = Rs. 50,000 Ajay's investment = Rs. 80,000 (after six months, which is equivalent to 0.5 years) Sanjay's additional investment after 1 year = Rs. 20,000 Total profit earned after 3 years = Rs. 7,02,000 First, let's calculate the total investment of Sanjay after 1 year: Sanjay's total investment after 1 year = Rs. 50,000 + Rs. 20,000 = Rs. 70,000 Next, let's adjust Ajay's investment for the same duration as Sanjay's total investment (3 years): Ajay's investment for 3 years = Rs. 80,000 * (3/2) = Rs. 1,20,000 Now, let's calculate the total investment: Total Investment = Sanjay's Investment + Ajay's Investment Total Investment = Rs. 70,000 + Rs. 1,20,000 Total Investment = Rs. 1,90,000 Next, we need to find the profit share of Sanjay based on his investment ratio: Sanjay's share = (Sanjay's Investment / Total Investment) * Total Profit Sanjay's share = (Rs. 70,000 / Rs. 1,90,000) * Rs. 7,02,000 Sanjay's share = (7/19) * Rs. 7,02,000 Sanjay's share = Rs. 2,58,000 So, the portion of the profits that goes to Sanjay is Rs. 2,58,000.
With respective investments of Rs. 30,000 and Rs. 45, 000, Mae and Kumari launched a business. What percentage of the earnings of Rs. 1,50,00,000 will belong to Kumari after two years?
Given: Mae's investment = Rs. 30,000 Kumari's investment = Rs. 45,000 Total earnings after two years = Rs. 1,50,00,000 Step 1: Calculate the total investment: Total investment = Mae's investment + Kumari's investment Total investment = Rs. 30,000 + Rs. 45,000 Total investment = Rs. 75,000 Step 2: Calculate the ratio of Kumari's investment to the total investment: Kumari's ratio = Kumari's investment / Total investment Kumari's ratio = Rs. 45,000 / Rs. 75,000 Kumari's ratio = 3/5 Step 3: Calculate Kumari's share of the earnings: Kumari's share = Kumari's ratio * Total earnings Kumari's share = (3/5) * Rs. 1,50,00,000 Kumari's share = Rs. 90,00,000